Diketahui f(x-2)=x²+3x dan g(x)=4x+1. rumus fungsi (f ° g) (x)=

⇔f(x-2) = x²+3x
⇔f((x+2)-2) = (x+2)²+3(x+2)
⇔f(x) = x²+4x+4+3x+6
⇔f(x) = x²+7x+10

⇔(f o g)(x) = f(g(x))
⇔(f o g)(x) = f(4x+1)
⇔(f o g)(x) = (4x+1)²+7(4x+1)+10
⇔(f o g)(x) = 16x²+8x+1+28x+7+10
⇔(f o g)(x) = 16x²+36x+18

∴ (f o g)(x) = 16x²+36x+18