Nilai dari

Jawaban:

= ²log 8 + 2² log 1/3 . ^√3log 64

= ²log 2³ + 2²log 3^-1 . ^√3log 64

= 3.(²log 2) + (-½).(²log3). 3^(½) log 2^6

= 3.(1) – ½. (²log 3). 6/(½). (³log 2)

= 3 – ½ . (²log 3). 12. (³log 2)

= 3 – ½ × 12. (²log 3. ³log 2)

= 3 – (½ × 12). ²log 2

= 3 – 6 . (1)

= -3. (1)

= -3