1/x + 1/y – 1/z = 6
2/x – 3/y + 1/z = 5
1/z – 1/y = -1
tentukan nilai :
a. x, y dan z
b. 2/x + 1/y – 3/z =……..
tolong di jb…
bsok d kumpul
Diketahui SPNTLV berikut
( a )
1/x + 1/y – 1/z = 6 |×2 | 2/x + 2/y – 2/z = 12
2/x – 3/y + 1/z = 5 |×1 | 2/x – 3/y + 1/z = 5
1/z – 1/y = -1 |×1 | 1/z – 1/y = -1
—:
5/y – 3/z = 7 | ×1 | 5/y – 3/z = 7
-1/y + 1/z = -1 | ×-5 | 5/y – 5/z = 5
—:
2/z = 12
z = 2/12 → 1/z = 6
—:
1/z – 1/y = -1
1/(2/12) – 1/y = -1
12/2 – 1/y = -1
-1/y = -1 + 6
-1/y = 5
y = -1/5 → 1/y = -5
—:
1/x + 1/y – 1/z = 6
1/x – 5 + 6 = 6
1/x = 5
x = 1/5
jadi
x = 1/5
y = -1/5
z = 1/6
( b ) 2/x + 1/y – 3/z = ….
2(5) + (-5) – 3(6) = ….
10 – 5 – 18 = -13
semoga membantu
tolong jadikan jawaban ter-brianly ya 🙂