Jika keliling persegi panjang ABCD 116cm,panjang AD (4x-2)cm dan lebar CD 2x cm..berapakah luasnya

2(4x-2 + 2x) = 116
6x -2 = 58
6x = 60
x = 10

jadi panjang =4(10)-2 = 38cm
lebar = 2(10)= 20cm

luas = 38cm x 20cm = 76cm^2

K = 2 X (P+L)
116 = 2 ((4x-2) + (2x)
116 = 2 (6x -2)
116 = 12x -4
120 = 12x
x = 10

panjang = 4.10-2 = 38
lebar = 2.10 = 20
luas = p x l = 38 x 20 = 760