Tentukan akar akar persamaan berikut dengan cara memfaktorkan!

Jawab:

a. (-x²-2x+3 )= 0 –> kalikan dengan (-1)

X²+2x-3=0

(X+3) (X-1)

X = (-3)

X = 1

Hp = {-3,1}

b. 2y²-5y-3 =0

(2y-6) (2y+1)

(y-3) (2y+1)

y = 3

y = -1/2

Hp = {-1/2, 3}

c. 2(x²+1) = x(x+3)

= 2x² + 2 = x² +3x

= 2x²-x²-3x +2 = 0

= x²-3x +2 = 0

= (x-1) (x-2)

X = 1

X = 2

Hp = {1,2}

d. 4x² = 16

X² = 16/4

X² = 4

X = 2

Hp = {2}

e. (X+2)² = 9

(X+2)(X+2) = 9

X²+2x+2x + 4 = 9

X²+4x+4-9 =0

X² +4x -5 =0

(X+5) (X-1)

X = -5

X = 1

Hp = {-5,1}

Semoga membantu

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