Tentukan akar-akar persamaan kuadrat : x²-8x-20=0

By Posted on

Tentukan akar-akar persamaan kuadrat : x²-8x-20=0

{x}^{2} - 8x - 20 \ = {x}^{2} + 2x - 10x - 20 \ = ( {x}^{2} + 2x) - (10x + 20) \ = x(x + 2) - 10(x + 2) \ = (x - 10)(x + 2)