Invers fungsi dari cos (x-phi/2)

Invers fungsi dari cos (x-phi/2)

Jawaban Terkonfirmasi

$y=cos{(x-frac{pi}{2})} \ y=sin(x) \ x=arcsin(y) \ f^{-1}(x)=arcsin(x)$

$f(x)=sqrt{x-1},g(x)=1-x^2 \ (f+g)(x)=f(x)+g(x)=sqrt{x-1}+(1-x^2) \ (f-g)(x)=f(x)-g(x)=sqrt{x-1}-(1-x^2) \ (f.g)(x)=f(x).g(x)=(1-x^2)sqrt{x-1} \ (f/g)(x)=f(x)/g(x)=frac{sqrt{x-1}}{1-x^2}=-frac{sqrt{x-1}}{x^2-1} \ -frac{sqrt{x-1}}{(x+1)(x-1)}=-frac{1}{(x+1)sqrt{x-1}}$