Diketahui f(x) = px+q,f(3) = 1 dan f(-1) = -7. nilai f (6) adalah​

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Diketahui f(x) = px+q,f(3) = 1 dan f(-1) = -7. nilai f (6) adalah​

f(x) = px + q

f(3) = 1

f(3) = 1

p(3) + q = 1

3p + q = 1

q = 1 – 3p

f(1) = 7

f(-1) = -7

p(-1) + q = -7

-p + q = -7

-p + (1 – 3p) = -7

-p + 1 – 3p = -7

-p – 3p = -7 – 1

-p – 3p = -8

-4p = -8

p = -8/-4

p = 2

Masukkan nilai p = 2 ke persamaan q = 1 – 3p

q = 1 – 3p

q = 1 – (3 × 2)

q = 1 – 6

q = -5

Mencari hasil f(6)

f(6) = p(6) + q

f(6) = 6p + q

f(6) = (6 × 2) + (-5)

f(6) = -12 – 5

f(6) = -17

Jadi, nilai f(6) adalah -17