16x kuadrat – 121 =0​

Jawab:

16x² – 121 = 0

(4x + 11)(4x – 11) = 0

4x + 11 = 0

4x = -11

x = -11/4

x = -2 3/4

4x – 11 = 0

4x = 11

x = 11/4

x = 2 3/4

Jawaban:

Gunakan rumus :

a² – b² = (a + b)(a – b)

sehingga :

16x² – 121 = 0

(4x)² – 11² = 0

(4x + 11)(4x – 11) = 0

x = -11/4 atau x = 11/4

semoga bermanfaat ^^