Diketahui akar-akar persamaan kuadrat 2x²-x+3=0 adalah x1 dan x2.nilai dari x1/x2+x2/x1

~Jawab~

Persamaan Kuadrat

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2x² – x + 3 = 0

a = 2, b = -1 , c = 3

• x1 + x2 = – b/a = – (-1)/2 = 1/2

• x1 . x2 = c/a = 3/2

Maka, x1/x2 + x2/x1 :

= x1/x2 + x2/x1

= ( (x1 + x2)² – 2 . x1 .x2 ) / (x1 . x2)

= ( (1/2)² – 2 . 3/2 ) / (3/2)

= ( (1/4) – 3 ) / (3/2)

= (- 11/4) / (3/2)

= – 11/4 × 2/3

= – 11/6 = – 1 5/6

Tandai sebagai jawaban tercerdas ya jika berkenan! thanks:)