Diket : HA = 0, 1M; Ka = 1 × 10 ^ – 5 Dit: PH
Jawaban:
3
Penjelasan:
[H+] = √Ka.Ma
=> √10^-5.10^-1
=> √10^-6
=> 10^-3
pH = – log [H+]
=> – log 10^-3
=> 3
Diket : HA = 0, 1M; Ka = 1 × 10 ^ – 5 Dit: PH
Jawaban:
3
Penjelasan:
[H+] = √Ka.Ma
=> √10^-5.10^-1
=> √10^-6
=> 10^-3
pH = – log [H+]
=> – log 10^-3
=> 3