Di ketahui f(x)=2x+1/x-3 dan g(x)=x+6 tentukan (gof)^-1(x)=​

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Di ketahui f(x)=2x+1/x-3 dan g(x)=x+6 tentukan (gof)^-1(x)=​

Jawab:

Penjelasan dengan langkah-langkah:

fungsi

f(x) = (2x + 1) / ( x – 3)

g(x) =  x + 6

gof(x) =  g{f(x)}

gof(x) =  f(x)  +6

sf gof(x) = dfrac{2x+1}{x-3} + 6sf\sf gof(x) = dfrac{2x+1 + 6(x -3)}{x-3}sf\sf gof(x) = dfrac{2x+1 + 6x -18}{x-3}sf\sf gof(x) = dfrac{8x - 17}{x-3}sf

y( x-  3) = 8x – 17

xy – 3y = 8x – 17

xy – 8x = 3y – 17

x(y -8) = 3y – 17

sf x= dfrac{3y-17}{y-8}sf\sf(fog)^{-1}(x) = dfrac{3x-17}{x - 8}