Please help me, this question has been bothering me for quite a while, help would be appreciated…
Jawaban Terkonfirmasi
∠DAE = 40° (alternate segment theorem)
∠ACD = 40° (angles in same segment are same)
∠CAE = 40° + 32° = 72°
then :
∠ACE + ∠AEC + ∠CAE = 180° (angles sum of a triangle)
40° + x + 72° = 180°
112° + x = 180°
x = 180° – 112°