Jika Persamaan Kuadrat a memiliki akar akar 3 dan – 4 , maka tentukan Bentuk Persmaan Kuadrat Tersebut !?

Jawaban:

x1 = 3

x2 = -4

Cara pertama

(x – x1)(x – x2) = 0

(x – 3)(x – (-4)) = 0

(x – 3)(x + 4) = 0

x(x + 4) – 3(x + 4) = 0

x² + 4x – 3x – 12 = 0

x² + x – 12 = 0

Cara kedua

x² – (x1 + x2)x + (x1 × x2) = 0

x² – (3 + (-4))x + (3 × (-4)) = 0

x² – (3 – 4)x + (-12) = 0

x² – (-1x) – 12 = 0

x² + x – 12 = 0

______________________________

(x – x1)(x – x2)

→ (x – 3)(x + 4)

→ x.x + 4x – 3x – 3.4

→ x² + x – 12