sebanyak 19,6 gram garam ch3cook (Mr=98) dilarutkan dalam air hingga volume 500 ml (Ka=1×10pangkat min lima ) carilah ph larutan ch3cook

[CH3COOK] = m/Mr x 1000/ml
= 19,6/98 x 1000/500
= 0,2 x 2
= 0,4 M

OH- = akar Kw/Ka [G]
= akar 10-14/10-5 (4/10-1)
= akar 4.10-10
= 2.10-5 M

poh = 5 – log 2
ph = 9 + log 2

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