Hitunglah ph larutan berikut a) HCl 0,25M b)Ba(OH)2 0,35M

A.
H+ = a Ma
= 1 x 0,25
= 2,5.10-1 M

ph = 1 – log 2,5

b.
OH- = b M
= 2 x 0,35
= 0,70 M

poh = 1 – log 7
ph = 13 + log 7

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