Hitunglah pH larutan dari 25 ml larutan CH3COOH 0,025 m (Ka=10 Pangkat min 5​

Jawaban:

pH = 5 – log 5

Penjelasan:

[H+] = √ka x Ma

= √10^-5 x 25×10^-3

= √25 x 10^-8

= 5 x 10^-4

pH = – log [H+]

= – log 5 x 10^-5

= 5 – log 5