Suatu fungsi f dinyatakan oleh f : X —> 2x + 1. jika domainnya {1,2,3,4}. tentukan :

Penyelesaian:

f(x) = 2x + 1

domainya {1,2,3,4}

Tentukan

=> x , jika f(x) = 11

f(x) = 2x +1

11. = 2x +1

10. = 2x

x. = 5

=> a, jika f(a) = 1

f(a) = 2a +1

1. = 2a +1

0 = 2a

a. = 0

Penyelesaian:

::: f(x) = 2x + 1

   11   = 2x +1

   2x = 10

    x = 5

::: f(a) = 2a +1

    1  = 2a +1

    0 = 2a

     a = 0