A. 2,7. 10^-10
B. 3,3 .10^-10
C. 3,3 .10^-20
D. 0,5 .10^-10
E. 0,5 .10^-13
Larutan jenuh L(OH)3 mempunyai pH = 9 . hasil kali kelarutan basa tersebut adalah…
Ph=9 pOH= 14-9=5 [OH^-]= 10^-5
[OH^-]= b. s -> L(OH)3 -> b= 3 .[OH^-] = 10^-5 –> 10^-5 = 3s -> s= 10^-5 / 3 Ksp = 27 s^4 = 27 (10^-5 / 3)^4 = 3,3.10^-21