Dik : 2Log3 = a Dit : a). 2Log27 b). 8Log9 c). 3Log16

By Posted on

Dik : 2Log3 = a
Dit : a). 2Log27
b). 8Log9
c). 3Log16

A) ²log27 = ²log 3.3.3 = ²log3 + ²log3 + ²log3 = a + a + a = 3a
b) ^{8} log9 = frac{log9}{log8} = frac{log3.3}{log.2.2.2} = frac{ ^{2} log3.3}{^{2} log.2.2.2} = frac{^{2} log3 + ^{2} log3}{^{2} log2 + ^{2} log2 + ^{2} log2} = frac{a+a}{1+1+1}= frac{2a}{3}
c) ^{3}log16 = frac{log16}{log3}= frac{ ^{2} log2.2.2.2}{ ^{2} log3}= frac{^{2} log2+^{2} log2+^{2} log2+^{2} log2}{^{2} log3} = frac{1+1+1+1}{a}= frac{4}{a}