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Jawaban:

2

Penjelasan dengan langkah-langkah:

syarat yang digunakan:

alogb + alogc = alog(bc)

alogb – alogc = alog(b/c)

Sehingga,

5log150 – 5log24 + 5log4

= 5log(150.4/24)

= 5log25

= 2

Jawaban:

2

Penjelasan dengan langkah-langkah:

5 log 150 – 5 log 24 + 5 log 4

= [5 log (25 × 2 × 3)] – [5 log (8 × 3)] + [5 log 2²]

= [5 log 25 + 5 log 2 + 5 log 3] – [5 log 8 + 5 log 3] + [5 log 2²]

= 5 log 5² + 5 log 2 + 5 log 3 – 5 log 2³ – 5 log 3 + 5 log 2²

= 2(5 log 5) + (5 log 2) + (5 log 3) – 3.(5 log 2) – (5 log 3)

= 2(1)

= 2