F(x) = x^2-x+3, (gof)(x) = 3x^2-3x+3 maka g(2-x) adalah

KOMPOSISI FUNGSI

g(f(x)) = 3x^2 – 3x + 3
g(x^2 – x + 3) = 3x^2 – 3x + 9 – 6
g(x^2 – x + 3) = 3(x^2 – x + 3) – 6
g(x) = 3x – 6

g(2-x) = 3(2-x) – 6
g(2-x) = 6 – 3x – 6
g(2-x) = -3x

misalkan :
a = x² – x + 3

g(f(x)) = 3x² – 3x + 3
g(a) = 3x² – 3x + 3
g(a) = 3(x² – x + 3) – 6
g(a) = 3a – 6

Jadi :
g(a) = 3a – 6
g(2 – x) = 3(2 – x) – 6
g(2 – x) = 6 – 3x – 6
g(2 – x) = – 3x