Diketahui bahwa f (x) = 2x + 3 dan g (x) = x – 2. Nilai dari f∘g (x) = ….​

f°g (x) = 2(x-2) + 3 = 2x-4+3 = 2x-1

Komposisi FUNgsi

f(x) = 2x + 3

g(x) = x – 2

(fog)(x)

= f(g(x))

= f(x – 2)

= 2(x – 2) + 3

= 2x – 4 + 3

= 2x – 1

(fog)(x) = 2x – 1