Sebanyak 4,9 gram h2so4 dilarutkan dalam 100 ml air.ph larutan tersebut

M = g x Mr/ V
= 4,9 x 98 / 0,1
= 0,5 M

[H+] = a x M
= 2 x 5 . 10^-1
= 10 x 10^-1

pH = -log [H+]
= -log 10 x 10^-1
= 1 – log10
=0