A. x + y =5
x – y = -1
B. x + 4y = 0
2x + y = 7
C. x + y = -3
2x – 2y = 10
Gunakan metode eliminasi, tentukan penyelesaian dari SPLDV berikut
A. x + y =5
x – y = -1___-
=>2y= 6
=>y= 6/2= 3
maka x
x + y = 5
x + 3 = 5
x= 5-3= 2
B. x + 4y = 0 x2 => 2x + 8y = 0
2x + y = 7 x1 => 2x + y = 7_______-
=> 7y = -7
=> y= -7/7 = -1
maka x
x + 4y= 0
x + 4(-1)= 0
x -4 = 0
x = 0+4= 4
C. x + y = -3 x2 => 2x + 2y= -6
2x – 2y = 10 x1 => 2x – 2y = 10______-
=> 4y= -16
=>y= -16/4 = -4
maka x
x + y= -3
x + (-4)= -3
x= -3+4
x= 1