Hasil dari integral(sin 3x-9 cos 2x)dx

Jawab

∫ (sin 3x – 9 cos 2x ) dx
= – 1/3 cos (3x)  – 9/2 sin (2x) + c

InTegraL

∫(sin 3x – 9cos 2x) dx
= ∫sin 3x dx – 9 ∫cos 2x dx
= -1/3 ∫dcos 3x – 9 . 1/2 ∫dsin 2x
= -1/3 cos 3x – 9/2 sin 2x + C ✔