Tolong bantuin dong :)

#F

no. 6

t tab = t kerucut= d bola = a

r tab = r krc = r bola = 1/2 a

Vt = π r² ttab

Vk = 1/3 π r² tk

V bola = 4/3 π r³

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Vt : Vk : Vb  =

= π r² t tab :  1/3 π r² tk  : 4/3 π r³

= πr² ( t tab : 1/3 tk : 4/3 r)

Perbandingan V Tab : V kerucut : V bola

= ttab : 1/3 tk : 4/3 r

=  a : 1/3 a :  4/3 (1/2) a

= a : 1/3 a : 2/3 a

= 1 : 1/3 : 2/3

= 3 : 1 : 2

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(4) √(x – 2 ) – √(x – 1)= 2

√(x – 2 )= 2 + √(x – 1)  

{√(x – 2 )}² = {2 + √(x – 1)}²

x – 2 = 4 +  4√(x – 1) + (x – 1)

4√(x – 1) =  x – 2 – 4 – (x – 1)

4√(x -1) = x – 6 – x + 1

4√(x – 1) = – 5

√( x-1) = – 5/4 —> tidak ada solusi

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