2 . 10 log 5 + 2 . 10 log 2

Materi : Eksponen dan Logaritma
Bahasan : Sifat – Sifat Logaritma
Jawaban : 2

Langkah – langkah :
ᵃlog b + ᵃlog c = ᵃlog (bc)
ᵃlog bˣ = x ᵃlog b

2 ¹⁰log 5 + 2 ¹⁰log 2
Berdasarkan sifat diatas, maka :
¹⁰log 5² + ¹⁰log 2²
= ¹⁰log 25 + ¹⁰log 4
= ¹⁰log (25 × 4)
= ¹⁰log 100
= ¹⁰log 10²
= 2 ¹⁰log 10
= 2(1)
= 2

2. ¹⁰log 5 + 2. ¹⁰log 2
= ¹⁰log 5² + ¹⁰log 2²
= ¹⁰log 25 + ¹⁰log 4
= ¹⁰log (25 x 4)
= ¹⁰log 100
= 2