Tentukan persamaan garis yang melalui titik (3,5)dan tegak lurus garis berikut!

a. m= -3/-1 = 3, m2 = -1/3

   y-y1 = m (x-x1)

  y-5 = -1/3 (x-3)

  3(y-5) = -1 (x-3)

  3y – 15 = -x + 3

  3y – 15 + x – 3 = 0

  3y + x – 18 = 0

b. m= -3/1, m2= 1/3

   y-y1 = m (x-x1)

  y-5 = 1/3 (x-3)

  3(y-5) = 1 (x-3)

  3y – 15 = x – 3

  3y – 15 – x + 3 = 0

  3y – x – 12 = 0

Maaf kalo salah…