Itegral pangkat 2 -1 (x pangkat 2 + x – 2) dx

Int [-1 s.d 2] (x² + x – 2) dx
= (1/3)x³ + (1/2)x² – 2x [-1 s.d 2]
= [(1/3)(8) + (1/2)(4) – 4] – [(1/3)(-1) + (1/2)(1) + 2]
= (8/3 + 2 – 4) – (-1/3 + 1/2 + 2)
= 8/3 – 2 + 1/3 – 1/2 – 2
= 3 – 4 – 1/2
= 7 – 1/2
= 13/2