243 pangakat 1/5 + 1/2 pangkat -3 – 1/3 pangkat 2
243^1/5 + (1/2)^-3 – (1/3)^2
= (3^5)^1/5 + 2^3 – (1/3)^2
= 3^1 + 2^3 – (1/3)^2
= 3 + 8 – 1/9
= 11 – 1/9
= 10 9/9 – 1/9
= 10 8/9
243 pangakat 1/5 + 1/2 pangkat -3 – 1/3 pangkat 2
243^1/5 + (1/2)^-3 – (1/3)^2
= (3^5)^1/5 + 2^3 – (1/3)^2
= 3^1 + 2^3 – (1/3)^2
= 3 + 8 – 1/9
= 11 – 1/9
= 10 9/9 – 1/9
= 10 8/9