Tolong bantu jawab, terima kasih​

Penjelasan dengan langkah-langkah:

Logaritma

√a = a^½

a log a = 1

a log n . ⁿlog c = a log c

a log b . a log c = a log (b + c)

a log b – a log c = a log (b / c)

maka,

= √2log 8 – ²log ½√2

= 2^½ log 2³ – ²log 2^-1 . 2^½

= 3/(½) (²log 2) – ²log 2^(-1 + ½)

= (3 . 2)(1) – ²log 2^(-2 + 1)/2

= 6 – ²log 2^(-1/2)

= 6 – (-1/2) (²log 2)

= 6 + 1/2

= (12 + 1)/2

= 13/2

= 6 ½

Jawaban : A