W1 = 30N W2 = 15 NHitung besar gaya tegangan talinya
Diketahui :
W1= 30N
W2 = 15N
<=> katrol bergerak ke arah W2. karena W1>W2
Ditanya :
gaya tegangan tali (T1+T2)
jawab:
(1)
W1 = m1 g
30=m1 (10)
m1= 30/10
m1= 3 Kg
W2 = m2 g
15 =m2 (10)
m2 = 15/10
m2 = 1,5 Kg
a= W/m
a= (30+15)/(3+1,5)
a= 45/4,5
a=
(2)
ΣF = ma
W1 – T1 = m1 a
(30) – T1 = (3) a
T1 = 30 – 3a
ΣF = ma
T2 – W2 = m2 a
T2 – (15) = (1,5) a
T2 = 15 + 1,5a
(3)
T1 = T2
30 – 3a = 15 + 1,5a
30 – 15 = 1,5a + 3a
15 = 4,5a
a = 15/4,5
a = 150/45
a = 10/3
(4)
subtitusi kan
a=10/3
T1 = 30-3(10/3)
T1 = 30-10
T1 = 20 N
T2 = 15+1,5(10/3)
T2 = 15 + 5
T2 = 20 N
Tegangan total = T1+T2 = 40N
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