Diketahui f(x)= x+4, g(x)=2x-1,maka nilai dari (fog)(x) (gof)(3) (fog0h)(x)

Diketahui f(x)= x+4, g(x)=2x-1,maka nilai dari (fog)(x) (gof)(3) (fog0h)(x)

Jawab:

Penjelasan dengan langkah-langkah:

$f(x) = x+4\g(x) = 2x-1\\(f o g)(x) = f(g(x))\(f o g)(x) = 2x-1+4\(f o g)(x)=2x+3\\(g o f)(x) = g(f(x))\(g o f)(x) = 2(x+4)-1\(g o f)(x) = 2x+7\(g o f)(3) =2(3)+7\(g o f)(3) =13$

Penjelasan dengan langkah-langkah:

f(x) = x + 4

g(x) = 2x – 1

maka nilai dari :

(fog)(x) = f(g(x))

= (2x – 1) + 4

= 2x – 1 + 4

= 2x + 3

(gof)(3) = g(f(3))

= 2(x + 4) – 1

= 2x + 8 – 1

= 2(3) + 8 – 1

= 6 + 8 – 1

= 13