Harga pH larutan NH4Cl 0,1 M jika diketahui kb NH4OH =10-5

NH4Cl 0,1 M , Kb = 10⁻⁵
[H+] = √Kw/Kb x M
[H+] = √10⁻¹⁴/10⁻⁵  x 0,1
[H+] = √10⁻¹⁰
[H+] = 10⁻⁵

pH = – log [H+]
pH = – log 10⁻⁵
pH = 5

Hidrolisis NH4Cl

H+ = √Kw/Ka x M
H+ = √10^-14/10^-5 x 0,1
H+ = 10^-5
pH = 5

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