Pls tolong mau di kumpul 5 menit

Pls tolong mau di kumpul 5 menit

Jawaban Terkonfirmasi

John's height is $boxed{bold{102~cm}}$

Data is needed in the analysis of a study or experiment

Data can be collected in the form of values

The data obtained can be expressed in the form of tables, graphs or diagrams

From the data distribution, it can be seen the frequency of the values

Mean is one way to get the average value from numerical data

Mean is the average value of some data. The mean value can be determined by dividing the sum of all data by the value of data

Can be formulated

$tt bar{x}=dfrac{x_1+x_2+x_3..x_n}{n}$

$tt bar{x}=dfrac{sum x_n}{n}$

Given

Average height of 5 pupils = 138 cm

The average changed to 130 when John and Raj joined

John is 16 cm shorter than Raj

Required

John's height

Solution

initial condition : 5 pupils

$tt 138=dfrac{sum x_n}{5}rightarrow sum x_n=138times 5 = 690~cm$

final condition : 7 pupils (John and Raj joined)

Raj = John + 16 cm

$tt 130=dfrac{sum x_n+John+Raj}{7}\\130=dfrac{690+John+John+16}{7}\\910=706+2.John\\204=2.JohnRightarrow John=102$

So John's height is $boxed{bold{102~cm}}$

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Grade : IX

Subject : Mathematics

Chapter : Statistics

Code : 9.2.6