Soal:
Permutasi dari kata :
"agathanov1411"
"irfanrafael10"
thnk u kk.
Ques [+50]
Penjelasan dengan langkah-langkah:
agathanov1411
a=3
1=3
Jumlah huruf=13
= 13!/3! ×3!
= 13×12×11×10×9×8×7×6×5×4×3×2×1/3×2×1 × 3×2×1
= 6.227.020.800/36
= 172.972.800 susunan kata
irfanrafael10
r=2
f=2
a=3
Jumlah huruf=13
= 13!/2!×2!×3!
= 13×12×11×10×9×8×7×6×5×4×3×2×1/2×1 × 2×1 × 3×2×1
= 6.227.020.800/24
= 259.459.200 susunan kata
Penjelasan dengan langkah-langkah:
"agathanov1411"
total unsur = 13 huruf
unsur ganda = a (3) 1 (3)
13!/3!.3!
= 13×12×11×10×9×8×7×6×5×4×3×2×1 / 3×2×1×3×2×1
= 6227020800/36
= 172.972.800susunan
"irfanrafael10"
total unsur = 13 huruf
unsur ganda = r (2) f (2) a (3)
13!/3!.2!.2!
= 13×12×11×10×9×8×7×6×5×4×3×2×1 / 3×2×1×2×1×2×1
= 6227020800 / 24
= 259.459.200 susunan