Tentukan nilai berikut A.tan 150 B.cos 330 C.sin 120+cos 210-tan 225

A.

tan 150
tan (180-30)
– tan 30 = -1/3√3

b.

cos 330
cos (360-30)
cos 30 = 1/2√3

c.
sin 120 + cos 210 – tan 225

sin 120 = 1/2√3
cos 210 = -1/2√3
tan 225 = 1

berarti 1/2√3 – 1/2√3 – 1 = -1

#semoga membantu

A. tan 150 = -tan a
= -tan(180-a)
= -tan (180-30)
= -tan 30
= -1/3 akar 3

B. cos 330 = cos a
= cos (360-a)
= cos(360-30)
= cos 30
= 1/2