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tentukan nilai dari
Q.
Jawab:
tan A = 1/3 = d/s
d= 1 , s= 3
m² = d²+s²= 1 +9
m = √10
sin A= d/m = 1/√10
cos A = s/m = 3/√10
sin 2A = 2 sin A cos A
sin 2A = 2 . (1/√10) (3/√10)
sin 2A = 6/10 = 3/5
trigonometri
tan 2a = 2 tan a / (1 – tan² a)
__
tan a = 1/3
tan 2a
= 2(1/3) / (1 – 1/9)
= 2/3 / (8/9)
= 3/4
tripel pythagoras → 3, 4, 5
sin 2a = 3/5