Q [300/300] - Universityku

$f(x) = 4 {x}^{2} + 3x - 27$
tentukan nilai dari f(7)

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Q [300/300]

f(x) = 4x² + 3x – 27

f(7) = 4(7)² + 3(7) – 27

f(7) = 4(49) + 21 – 27

f(7) = 196 + 21 – 27

f(7) = 217 – 27

f(7) = 190

$f(x) = 4 {x}^{2} + 3x - 27 \ f(7) = 4 {(x)}^{2} + 3x - 27 \ f(7) = 4 {(7)}^{2} + 3(7) - 27 \ f(7) = 4(49) + 21 - 27 \ f(7) = 196 + 21 - 27 \ f(7) = 217 - 27 \ f(7) = 190$

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