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Jawaban:

Integral Tentu

²integral-1 (3x² – 2x + 1) dx

²integral-1 (3x²+¹/2+1) – (2x¹+¹/1+1) + x + C

²integral-1 (3x³/3) – (2x²/2) + x + C

= x³ – x² + x + C

maka, batas atas –> 2 dan batas bawah —> -1

= (x³ – x² + x) – (x³ – x² + x)

= (2³ – 2² + 2) – (-1³ – (-1)² + (-1))

= (8 – 4 + 2) – (-1 – 1 – 1)

= (6) – (-3)

= 6 + 3

= 9

Opsi (D). 9