1. mx2 + 2mx – 1 = 0
2. x2 – 3mx + (4m+1) = 0
Persamaan berikut memiliki akar kembar. tentukan nilai m!
Jawaban Terkonfirmasi
Syarat akar kembar D = 0
1. mx² + 2mx – 1 = 0
D = 0
b² – 4ac = 0
(2m)² – 4(m)(-1) = 0
4m² + 4m = 0
4m (m + 1) = 0
m = 0 atau m = -1
2. x² – 3mx + (4m + 1) = 0
b² – 4ac = 0
(-3m)² – 4(1)(4m + 1) = 0
9m² – 16m – 4 = 0
(9m + 2)(m – 2) = 0
m = -2/9 atau m = 2