Berapakah panjang PQ ?
AB/X = BD/PD
10/X = (2+3)/2
5X = 20/5
X= 4
DC/(PQ+X) = AC/AQ
20/(PQ+4) = (3+2)/3
5(PQ+4) = 20X3
PQ+4 = 60/5
PQ+4 =12
PQ=12-4
PQ=8 CM
SWMOGA MEMBANTU
MAAF KALAU SALAH:)
Berapakah panjang PQ ?
AB/X = BD/PD
10/X = (2+3)/2
5X = 20/5
X= 4
DC/(PQ+X) = AC/AQ
20/(PQ+4) = (3+2)/3
5(PQ+4) = 20X3
PQ+4 = 60/5
PQ+4 =12
PQ=12-4
PQ=8 CM
SWMOGA MEMBANTU
MAAF KALAU SALAH:)