PH larutan 100 ml NH4Cl 0,1 M adalah (Kb = 10^-5)
Jawaban Terkonfirmasi
NH4Cl 0,1 M , Kb = 10⁻⁵
[H+] = √Kw/Kb x M
[H+] = √10⁻¹⁴/10⁻⁵ x 0,1
[H+] = √10⁻¹⁰
[H+] = 10⁻⁵
pH = – log [H+]
pH = – log 10⁻⁵
pH = 5
PH larutan 100 ml NH4Cl 0,1 M adalah (Kb = 10^-5)
NH4Cl 0,1 M , Kb = 10⁻⁵
[H+] = √Kw/Kb x M
[H+] = √10⁻¹⁴/10⁻⁵ x 0,1
[H+] = √10⁻¹⁰
[H+] = 10⁻⁵
pH = – log [H+]
pH = – log 10⁻⁵
pH = 5