Jika fungsi kuadrat y= x pankat2 -7x + 10 cari lah koordinat titik puncak

Jawab:

Penjelasan dengan langkah-langkah:

a =1, b = – 7 , c= 10

x = -b/2a = -(-7)/2.1 = 7/2

y =(7/2)² – 7.7/2 + 10

y = 49/4 – 49/2 + 10

y = -9/4

titik puncak (7/2,- 9/4)

Y=x²-7x+10
a=1,b=-7,c=10

y=(-b/2.a , -(b²-4.a.c/4.a))
y=(-(-7)/2.1 , -(-7²-4.1.10/4.1))
y=(7/2 , -(49-40/4))
y=(3 1/2, -9/4)
y=(3 1/2, -2 1/4)
maaf kalau salah