Kk bantuin kk ~~~~~~~~

Kk bantuin kk ~~~~~~~~

luas segitiga ABC = 1/2 x 19 x 12 = 114

luas BCD = 1/2 x 10 x 12 = 60

luas yg diarsir = 114-60 = 54

$ps = sqrt{ {48}^{2} + {64}^{2} } = sqrt{2304 + 4096} \ = sqrt{6400} = 80$

$sr = sqrt{ {48}^{2} + {36}^{2} } = sqrt{2304 + 1296} \ = sqrt{3600} = 60$

kelilingnya adalah 2(80) + 2(60) = 160+120= 280