Tentukan akar akar atau penyelesaian dari persamaan kuadrat berikut!
1. x²+ 6x = 0
2. 2x² + 5x = 0
3. 9x²-64 = 0
4. x² + 6x +8=0
5. X²-7x + 12 = 0
Kerjakan soal berikut!
Jawab:
1. x (x + 6) = 0
(x + 3)^2 – 9 = 0
x = -6
x = 0
2. x (2 x + 5) = 0
2 (x + 5/4)^2 – 25/8 = 0
x = -5/2
x = 0
3. 9 x^2 = 64
(3 x – 8) (3 x + 8) = 0
x = -8/3
x = 8/3
4. (x + 2) (x + 4) = 0
(x + 3)^2 – 1 = 0
x = -4
x = -2
5. x = X^2/7 + 12/7
X = -sqrt(7 x – 12)
X = sqrt(7 x – 12)
x = 7 n^2 – 8 n + 4, X = 4 – 7 n, n element Z
x = 7 n^2 – 6 n + 3, X = 3 – 7 n, n element Z
x = 1/7 (X^2 + 12)
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