Q.f(x) = x²(x) – x²(2) f(5) =nothing________________​

f(x) = x²(x) – x²(2)

f(5) = 5²(5) – 5²(2)

f(5) = (5 × 5)(5) – (5 × 5)(2)

f(5) = 25(5) – 25(2)

f(5) = 125 – 50

f(5) = 75

Ninmy!

f(x) = x²(x) – x²(2)

f(5) = …

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f(5) = 5²(5) – 5²(2)

f(5) = 5.5(5) – 5.5(2)

f(5) = 25(5) – 25(2)

f(5) = 125 – 50

f(5) = 75