Mintaa tolong bantuin kak

Penjelasan dengan langkah-langkah:

lim

x→6v(3r-2) – v(2r+4)/ r-6. × (3r-2) +v(2r+4)/(3r-2) + v(2r+4)

lim. (3r-2)-(2r+4)/(r-6) (v(3r-2) + v(2r+4))

x→6

lim. r-6/(r-6) (v(3r-2) + v(2r+4))

x→6

lim. 1 / v(3r-2) + v(2r+4)

x→6

1/ (16+ 16) = 1/32