ALJABAR UJIAN KELAS 7​

Jawaban:

a. 5r – 3p + 8s

b. 20a + 6b – 5c + 12

c. 15x + 13z

Penjelasan dengan langkah-langkah:

a. (4r + p + 3s) + (r – 4p + 5s) =

(4r + r) + (p – 4p) + (3s + 5s) =

5r + (-3p) + 8s = 5r – 3p + 8s

b. (11a – b – 5c + 4) + (9a + 7b + 8) =

(11a + 9a) + (- b + 7b) – 5c + (4+8) =

20a + 6b – 5c + 12

c. (8x – 7y + 6z) + (7x + 7y + 7z) =

(8x + 7x) + (-7y + 7y) + (6z + 7z) =

15x + 0 + 13z = 15x + 13z

2. a. 4r + p + 3s + r – 4p + 5s

= 4r + r + p – 4p + 3s + 5s

= 5r – 3p + 8s

b. 11a – b – 5c + 4 + 9a + 7b + 8

= 11a + 9a – b + 7b – 5c + 4 + 8

= 20a + 6b – 5c + 12

c. 8x – 7y + 6z + 7x + 7y + 7z

= 8x + 7x – 7y + 7y + 6z + 7z

= 15x + 13z